KPK Board 12th class Chemistry Ch 13 S and P Block Elements short questions answers
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Malakand Board 12th classes short questions Answer
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Mg + H2O à MgO + H2
(b) Chlorine and describe the product.
As we go down the group IA the reactivity of elements increases due to increases in their metallic character. So rubidium can react vigorously with water and chlorine.
- Atomic radius of this group increases down the group.
- Ionization energy of 2nd a group decreases down the group.
- Electronegativity also decreases down the group.
- These group elements have high melting and boiling point.
So BeCl2 is covalent in nature.
Basic: Be(OH)2 +HClàBeCl2+H2o
Aluminum: Aluminum has lower ionization energy because in Aluminum the last electron is in 3pix which is higher energy orbital, which means it is farther from nucleus. So it can easily be removed, which result decrease in ionization energy of Aluminum.
Sulphur: Sulphur also has unexpected lower ionization energy because of the presence of an extra electron in p orbital i.e. it is ns2 np4 system and extra electron is present in 3px orbital which result in electron-electron repulsion. So electron could be removed easily that result decrease in ionization energy sulphur.